If P(A)=0.8, P(B)=0.5 and P(B | A)=0.4, find | vedclass

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(A) Given that $P(A)=0.8, P(B)=0.5$ and $P(B | A)=0.4.$We know that the conditional probability formula is $P(B | A) = \frac{P(A \cap B)}{P(A)}.$Subst

Vedclass · Accepted Answer

$0.64$

Vedclass · Answer

(A) Given that $P(A)=0.8, P(B)=0.5$ and $P(B | A)=0.4.$We know that the conditional probability formula is $P(B | A) = \frac{P(A \cap B)}{P(A)}.$Substituting the values,we get $0.4 = \frac{P(A \cap B)}{0.8}.$Therefore,$P(A \cap B) = 0.4 	imes 0.8 = 0.32.$Now,we need to find $P(A | B).$Using the formula $P(A | B) = \frac{P(A \cap B)}{P(B)},$$P(A | B) = \frac{0.32}{0.5} = 0.64.$

If $P(A)=0.8, P(B)=0.5$ and $P(B | A)=0.4,$ find $P(A | B).$

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