If 1.2 , g of a metal displaces 1.12 , L of h | vedclass

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Question

(A) The equivalent weight of a metal is defined as the mass of the metal that displaces $1 \, g$ of hydrogen or $11.2 \, L$ of hydrogen at $STP$.Given

Vedclass · Accepted Answer

$12$

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(A) The equivalent weight of a metal is defined as the mass of the metal that displaces $1 \, g$ of hydrogen or $11.2 \, L$ of hydrogen at $STP$.Given that $1.12 \, L$ of $H_2$ is displaced by $1.2 \, g$ of metal.Therefore,$1 \, L$ of $H_2$ is displaced by $\frac{1.2}{1.12} \, g$ of metal.Thus,$11.2 \, L$ of $H_2$ is displaced by $\frac{1.2}{1.12} 	imes 11.2 = 12 \, g$ of metal.Hence,the equivalent weight of the metal is $12$.

If $1.2 \, g$ of a metal displaces $1.12 \, L$ of hydrogen at $STP$,the equivalent weight of the metal would be:

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