If $A=\{3, 6, 9, 12, 15, 18, 21\}, B=\{4, 8, 12, 16, 20\}, C=\{2, 4, 6, 8, 10, 12, 14, 16\}, D=\{5, 10, 15, 20\};$ find $A-C$.

If $A$ and $B$ are any two non-empty sets and $A$ is a proper subset of $B$. If $n(A) = 4$,then the minimum possible value of $n(A \Delta B)$ is (where $\Delta$ denotes the symmetric difference of set $A$ and set $B$).

Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$.
Describe the event $A \cap B^{\prime} \cap C^{\prime}$.

If $A, B$ and $C$ are non-empty sets,then $(A - B) \cup (B - A)$ equals:

Let $A = \{a, b, c\}, B = \{b, c, d\}, C = \{a, b, d, e\}$. Then $A \cap (B \cup C)$ is:

Let $A$ and $B$ be two sets,then $(A \cup B)' \cup (A' \cap B)$ is equal to