If $1 \ g$ of each of the following gases are taken at $STP$,which of the gases will occupy $(a)$ greatest volume and $(b)$ smallest volume? $CO, H_2O, CH_4, NO$

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(N/A) From Avogadro's law,the volume of $1 \ mol$ of any gas at $STP$ is $22.4 \ L$.
The volume occupied by $1 \ g$ of a gas is given by $\frac{22.4 \ L}{\text{Molar mass in } g \ mol^{-1}}$.
$1$. For $CO$ (Molar mass $= 28 \ g \ mol^{-1}$): Volume $= \frac{22.4}{28} = 0.80 \ L$.
$2$. For $H_2O$ (Molar mass $= 18 \ g \ mol^{-1}$): Volume $= \frac{22.4}{18} \approx 1.24 \ L$.
$3$. For $CH_4$ (Molar mass $= 16 \ g \ mol^{-1}$): Volume $= \frac{22.4}{16} = 1.40 \ L$.
$4$. For $NO$ (Molar mass $= 30 \ g \ mol^{-1}$): Volume $= \frac{22.4}{30} \approx 0.75 \ L$.
Comparing the volumes,$CH_4$ occupies the greatest volume $(1.40 \ L)$ and $NO$ occupies the smallest volume $(0.75 \ L)$.

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Match the following:
Column-$I$ Column-$II$
$A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$ $I$. $32 \ g$
$B$. $1.2 \times 10^{24}$ atoms of oxygen $II$. $66 \ g$
$C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$ $III$. $42 \ g$
$D$. $1.5 \ g$-molecule of $N_2$ $IV$. $16 \ g$

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