If $\lambda_{m}^{o}(SO_{4}^{2-}) = 160 \ S \ cm^{2} \ mol^{-1}$ and $\Lambda_{m}^{o}(Al_{2}(SO_{4})_{3}) = 758 \ S \ cm^{2} \ mol^{-1}$,then calculate $\lambda_{m}^{o}(Al^{3+})$.

  • A
    $139 \ S \ cm^{2} \ mol^{-1}$
  • B
    $189 \ S \ cm^{2} \ mol^{-1}$
  • C
    $239 \ S \ cm^{2} \ mol^{-1}$
  • D
    $339 \ S \ cm^{2} \ mol^{-1}$

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