If 5A = 12B = 13C,find A:B:C. | vedclass

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(A) Given the equation $5A = 12B = 13C = k$ (where $k$ is a constant).Then,$A = k/5$,$B = k/12$,and $C = k/13$.To find the ratio $A:B:C$,we have $k/5

Vedclass · Accepted Answer

$156: 65: 60$

Vedclass · Answer

(A) Given the equation $5A = 12B = 13C = k$ (where $k$ is a constant).Then,$A = k/5$,$B = k/12$,and $C = k/13$.To find the ratio $A:B:C$,we have $k/5 : k/12 : k/13$.Dividing by $k$,we get $1/5 : 1/12 : 1/13$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of $5, 12,$ and $13$.$LCM(5, 12, 13) = 5 	imes 12 	imes 13 = 780$.Multiplying each term by $780$:$A = 780 / 5 = 156$$B = 780 / 12 = 65$$C = 780 / 13 = 60$Therefore,$A:B:C = 156: 65: 60$.

If $5A = 12B = 13C$,find $A:B:C$.

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