If frac{x}{y} = frac{3}{4},then the value of | vedclass

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(C) Given that $\frac{x}{y} = \frac{3}{4}$,we can express $x$ as $x = \frac{3}{4}y$.Substitute $x = \frac{3}{4}y$ into the expression $\frac{y-x}{y+x}

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$1$

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(C) Given that $\frac{x}{y} = \frac{3}{4}$,we can express $x$ as $x = \frac{3}{4}y$.Substitute $x = \frac{3}{4}y$ into the expression $\frac{y-x}{y+x}$:$\frac{y - \frac{3}{4}y}{y + \frac{3}{4}y} = \frac{\frac{1}{4}y}{\frac{7}{4}y} = \frac{1}{7}$.Now,add this to the first term:$\frac{6}{7} + \frac{1}{7} = \frac{7}{7} = 1$.

If $\frac{x}{y} = \frac{3}{4}$,then the value of $\left(\frac{6}{7} + \frac{y-x}{y+x}\right)$ equals:

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