If 34N is a two-digit number divisible by 11, | vedclass

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(A) number is divisible by $11$ if the difference between the sum of digits at odd places and the sum of digits at even places is either $0$ or a mult

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$1$

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(A) number is divisible by $11$ if the difference between the sum of digits at odd places and the sum of digits at even places is either $0$ or a multiple of $11$.For the number $34N$,the digits are $3$ and $4N$ (where $N$ is the units digit).Let the number be represented as $34N$. The digits are $3, 4, N$.The alternating sum is $(3 + N) - 4$.For the number to be divisible by $11$,this difference must be $0$ or a multiple of $11$.$(3 + N) - 4 = 0$$N - 1 = 0$$N = 1$.Thus,the number is $341$,which is $11 	imes 31$.

If $34N$ is a two-digit number divisible by $11$,then what is the value of $N$?

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