If $\frac{1}{2}$ is added to a number and the sum is multiplied by $3,$ the result is $21.$ Then the number is (in $.5$)

  • A
    $6$
  • B
    $5$
  • C
    $4$
  • D
    $6$

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What least number should be subtracted from $3401$ so that the result is completely divisible by $11$?

Which number should replace both the $*$s in $\left(\frac{*}{21}\right) \times \left(\frac{*}{189}\right) = 1$?

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