If frac{1}{6} of x - frac{7}{2} of frac{3}{7} | vedclass

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(A) Given the equation: $\frac{1}{6}x - (\frac{7}{2} 	imes \frac{3}{7}) = -\frac{7}{4}$Simplify the term $\frac{7}{2} 	imes \frac{3}{7}$ by cancelin

Vedclass · Accepted Answer

$-1.5$

Vedclass · Answer

(A) Given the equation: $\frac{1}{6}x - (\frac{7}{2} 	imes \frac{3}{7}) = -\frac{7}{4}$Simplify the term $\frac{7}{2} 	imes \frac{3}{7}$ by canceling $7$ from the numerator and denominator:$\frac{1}{6}x - \frac{3}{2} = -\frac{7}{4}$Add $\frac{3}{2}$ to both sides:$\frac{x}{6} = -\frac{7}{4} + \frac{3}{2}$Find a common denominator for the right side:$\frac{x}{6} = -\frac{7}{4} + \frac{6}{4} = -\frac{1}{4}$Multiply both sides by $6$ to solve for $x$:$x = -\frac{1}{4} 	imes 6 = -\frac{6}{4} = -1.5$

If $\frac{1}{6}$ of $x - \frac{7}{2}$ of $\frac{3}{7}$ equals $-\frac{7}{4},$ then the value of $x$ is

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