If $x = (0.25)^{\frac{1}{2}}, y = (0.5)^{2}, z = (0.216)^{\frac{1}{3}},$ then

If $x+y+z=1, xy+yz+zx=-1, xyz=-1,$ then $x^{3}+y^{3}+z^{3}$ is

Simplify $\frac{2 \frac{1}{7}-2 \frac{1}{2}}{2 \frac{1}{4}+1 \frac{1}{7}} \div \frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}$

If the square of the sum of three positive consecutive natural numbers exceeds the sum of their squares by $292$,then what is the largest of the three numbers?

The simplification of $1+\frac{1}{1+\frac{1}{1-\frac{2}{3}}}$ yields the result

The value of $\frac{(0.96)^{3}-(0.1)^{3}}{(0.96)^{2}+0.096+(0.1)^{2}}$ is