If sqrt{1+frac{x}{144}}=frac{13}{12}, then x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the equation: $\sqrt{1+\frac{x}{144}} = \frac{13}{12}$Square both sides of the equation to remove the square root:$1 + \frac{x}{144} = \left

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) Given the equation: $\sqrt{1+\frac{x}{144}} = \frac{13}{12}$Square both sides of the equation to remove the square root:$1 + \frac{x}{144} = \left(\frac{13}{12}\right)^2$$1 + \frac{x}{144} = \frac{169}{144}$Subtract $1$ from both sides:$\frac{x}{144} = \frac{169}{144} - 1$$\frac{x}{144} = \frac{169 - 144}{144}$$\frac{x}{144} = \frac{25}{144}$Multiplying both sides by $144$,we get:$x = 25$

If $\sqrt{1+\frac{x}{144}}=\frac{13}{12},$ then $x$ equals to

Similar Questions

If $(\frac{5}{9} \text{ of } x) - (\frac{2}{5} \text{ of } \frac{9}{4}) = -\frac{4}{5}$,then find $x$.

If $x = y = 333$ and $z = 334$,then the value of $x^{3} + y^{3} + z^{3} - 3xyz$ is

Between two fractions $\frac{1}{2}$ and $\frac{1}{8},$ how many fractions are there in all?

What mathematical operation should come at the place of $?$ in the equation $2 ? 6 - 12 \div 4 + 2 = 11$?

$(8 \div 88) \times 8888088 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module