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Question

(A) Given the quadratic equation $4x^2 + 3x + 7 = 0$.Comparing this with the standard form $ax^2 + bx + c = 0$,we have $a = 4$,$b = 3$,and $c = 7$.Acc

Vedclass · Accepted Answer

$-\frac{3}{7}$

Vedclass · Answer

(A) Given the quadratic equation $4x^2 + 3x + 7 = 0$.Comparing this with the standard form $ax^2 + bx + c = 0$,we have $a = 4$,$b = 3$,and $c = 7$.According to the relationship between roots and coefficients:Sum of roots $\alpha + \beta = -\frac{b}{a} = -\frac{3}{4}$.Product of roots $\alpha\beta = \frac{c}{a} = \frac{7}{4}$.We need to find the value of $\frac{1}{\alpha} + \frac{1}{\beta}$.Taking the common denominator,we get $\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta}$.Substituting the values,$\frac{-3/4}{7/4} = -\frac{3}{4} 	imes \frac{4}{7} = -\frac{3}{7}$.

If $\alpha$ and $\beta$ are the roots of the equation $4x^2 + 3x + 7 = 0$,then $\frac{1}{\alpha} + \frac{1}{\beta} =$

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