If a and b are roots of x^2 - px + q = 0,then | vedclass

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(D) Given the quadratic equation $x^2 - px + q = 0$.Let $a$ and $b$ be the roots of the equation.According to the relationship between roots and coeff

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$\frac{p}{q}$

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(D) Given the quadratic equation $x^2 - px + q = 0$.Let $a$ and $b$ be the roots of the equation.According to the relationship between roots and coefficients:Sum of roots: $a + b = -(	ext{coefficient of } x) / (	ext{coefficient of } x^2) = -(-p) / 1 = p$.Product of roots: $ab = (	ext{constant term}) / (	ext{coefficient of } x^2) = q / 1 = q$.Now,we need to find the value of $\frac{1}{a} + \frac{1}{b}$.$\frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}$.Substituting the values of $(a + b)$ and $(ab)$,we get $\frac{p}{q}$.

If $a$ and $b$ are roots of $x^2 - px + q = 0$,then $\frac{1}{a} + \frac{1}{b} = $

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