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(D) Given that $a, b, c$ are in $A.P.$,we have the property $2b = a + c$.Now,substitute $2b = a + c$ into the given expression $(a + 2b - c)(2b + c -

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$4abc$

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(D) Given that $a, b, c$ are in $A.P.$,we have the property $2b = a + c$.Now,substitute $2b = a + c$ into the given expression $(a + 2b - c)(2b + c - a)(c + a - b)$:$1$. First term: $(a + 2b - c) = (a + (a + c) - c) = 2a$.$2$. Second term: $(2b + c - a) = ((a + c) + c - a) = 2c$.$3$. Third term: $(c + a - b) = (2b - b) = b$ (since $a + c = 2b$).Multiplying these terms together:$(2a) 	imes (2c) 	imes (b) = 4abc$.Therefore,the correct option is $D$.

If $a, b, c$ are in $A.P.$,then $(a + 2b - c)(2b + c - a)(c + a - b)$ equals

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