If $\sin \theta + \csc \theta = 2$,then $\sin^2 \theta + \csc^2 \theta = $

  • A
    $1$
  • B
    $4$
  • C
    $2$
  • D
    None of these

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Let $A, B, C$ be three angles such that $\sin A + \sin B + \sin C = 0$. Then,$\frac{\sin A \sin B \sin C}{\sin 3A + \sin 3B + \sin 3C}$ (wherever defined) is equal to:

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