If sin theta + cos theta = 1,then sin theta c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: $\sin 	heta + \cos 	heta = 1$Squaring both sides of the equation,we get:$(\sin 	heta + \cos 	heta)^2 = 1^2$Using the identity $(a + b)^

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) Given: $\sin 	heta + \cos 	heta = 1$Squaring both sides of the equation,we get:$(\sin 	heta + \cos 	heta)^2 = 1^2$Using the identity $(a + b)^2 = a^2 + b^2 + 2ab$:$\sin^2 	heta + \cos^2 	heta + 2 \sin 	heta \cos 	heta = 1$We know the trigonometric identity $\sin^2 	heta + \cos^2 	heta = 1$:$1 + 2 \sin 	heta \cos 	heta = 1$Subtracting $1$ from both sides:$2 \sin 	heta \cos 	heta = 0$Dividing by $2$:$\sin 	heta \cos 	heta = 0$

If $\sin \theta + \cos \theta = 1$,then $\sin \theta \cos \theta = $

Similar Questions

If $b \sin \alpha = a \sin (\alpha + 2\beta)$,then $\frac{a + b}{a - b} = $

The value of $\frac{\sin 300^{\circ} \tan 240^{\circ} \sec \left(-420^{\circ}\right)}{\cot \left(-315^{\circ}\right) \cos \left(210^{\circ}\right) \operatorname{cosec}\left(-315^{\circ}\right)}$ is

The value of $\sec ^{2} \theta - \frac{\sin ^{2} \theta - 2 \sin ^{4} \theta}{2 \cos ^{4} \theta - \cos ^{2} \theta}$ is

Given the equation $4x^2 + 4(a - 1)x + (1 - 2a) = 0$ has roots $\sin \theta$ and $\cos \theta$ where $0 < \theta < \frac{\pi}{2}$,then the maximum value of $(a + \sin \theta)$ is:

If $\theta$ and $\phi$ are angles in the $1^{st}$ quadrant such that $\tan \theta = 1/7$ and $\sin \phi = 1/\sqrt{10}$. Then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module