If sin theta = - frac{1}{sqrt{2}} and tan the | vedclass

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(C) Given that $\sin 	heta = - \frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.$1$. The value of $\sin 	heta$ is negative,which implies that $	heta$ must

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(C) Given that $\sin 	heta = - \frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.$1$. The value of $\sin 	heta$ is negative,which implies that $	heta$ must lie in either the third or fourth quadrant.$2$. The value of $	an 	heta$ is positive,which implies that $	heta$ must lie in either the first or third quadrant.$3$. For both conditions to be satisfied simultaneously,$	heta$ must lie in the third quadrant,where both $\sin 	heta$ is negative and $	an 	heta$ is positive.Therefore,$	heta$ lies in the third quadrant.

If $\sin \theta = - \frac{1}{\sqrt{2}}$ and $\tan \theta = 1$,then $\theta$ lies in which quadrant?

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