If x = sec theta + tan theta , then x + frac{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that $x = \sec 	heta + 	an 	heta$.We know the identity $\sec^2 	heta - 	an^2 	heta = 1$,which can be written as $(\sec 	heta - 	an \

Vedclass · Accepted Answer

$2 \sec 	heta$

Vedclass · Answer

(B) Given that $x = \sec 	heta + 	an 	heta$.We know the identity $\sec^2 	heta - 	an^2 	heta = 1$,which can be written as $(\sec 	heta - 	an 	heta)(\sec 	heta + 	an 	heta) = 1$.Therefore,$\frac{1}{x} = \frac{1}{\sec 	heta + 	an 	heta} = \sec 	heta - 	an 	heta$.Now,calculating $x + \frac{1}{x}$:$x + \frac{1}{x} = (\sec 	heta + 	an 	heta) + (\sec 	heta - 	an 	heta)$.$x + \frac{1}{x} = 2 \sec 	heta$.

If $x = \sec \theta + \tan \theta ,$ then $x + \frac{1}{x} = $

Similar Questions

If $2y \cos \theta = x \sin \theta$ and $2x \sec \theta - y \csc \theta = 3$,then $x^2 + 4y^2 = $

If $0^{\circ} < \theta < 90^{\circ},$ the value of $\sin \theta + \cos \theta$ is

The value of $\sin 10^\circ \sin 30^\circ \sin 50^\circ \sin 70^\circ$ is

$\frac{\tan ^{2} \theta}{\sec \theta+1}-\sec \theta$ is equal to

The radius of the circle whose arc of length $15 \ cm$ makes an angle of $3/4$ radian at the centre is ..... $cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module