If $\cos x + \cos^2 x = 1$,then the value of $\sin^2 x + \sin^4 x$ is

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $2$

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The value of the following expression is $3(\sin^{4} \theta + \cos^{4} \theta) + 2(\sin^{6} \theta + \cos^{6} \theta) + 12\sin^{2} \theta \cos^{2} \theta$.

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