If theta is an acute angle and sintheta = fra | vedclass

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(B) Since $	heta$ is an acute angle,we have $0^\circ < 	heta < 90^\circ$.For an acute angle,the value of $\sin	heta$ must satisfy $0 \le \sin	heta

Vedclass · Accepted Answer

$6 \le p < 7$

Vedclass · Answer

(B) Since $	heta$ is an acute angle,we have $0^\circ For an acute angle,the value of $\sin	heta$ must satisfy $0 \le \sin	heta Substituting the given expression: $0 \le \frac{p - 6}{8 - p} First,consider $0 \le \frac{p - 6}{8 - p}$. Since the denominator $8 - p$ must be positive for $\sin	heta$ to be defined and positive,we have $8 - p > 0$,which implies $p Next,consider $\frac{p - 6}{8 - p}  0$,we can multiply both sides by $(8 - p)$ without changing the inequality sign: $p - 6 Adding $p$ to both sides: $2p - 6 Adding $6$ to both sides: $2p Dividing by $2$: $p Combining the conditions $p \ge 6$ and $p < 7$,we get $6 \le p < 7$.

If $\theta$ is an acute angle and $\sin\theta = \frac{p - 6}{8 - p}$,then $p$ must satisfy:

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