If m = -4 and n = -2,then the value of m^{3} | vedclass

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(D) Given: $m = -4$ and $n = -2$.We need to evaluate the expression: $m^{3} - 3m^{2} + 3m + 3n + 3n^{2} + n^{3}$.To simplify,we can rearrange the term

Vedclass · Accepted Answer

$-126$

Vedclass · Answer

(D) Given: $m = -4$ and $n = -2$.We need to evaluate the expression: $m^{3} - 3m^{2} + 3m + 3n + 3n^{2} + n^{3}$.To simplify,we can rearrange the terms to form perfect cubes:$(m^{3} - 3m^{2} + 3m - 1) + (n^{3} + 3n^{2} + 3n + 1) = 0$Note that we subtracted $1$ and added $1$ to keep the expression equivalent.This simplifies to: $(m - 1)^{3} + (n + 1)^{3}$.Now,substitute the values of $m$ and $n$:$(-4 - 1)^{3} + (-2 + 1)^{3}$$= (-5)^{3} + (-1)^{3}$$= -125 - 1$$= -126$.

If $m = -4$ and $n = -2$,then the value of $m^{3} - 3m^{2} + 3m + 3n + 3n^{2} + n^{3}$ is

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