If $x+\frac{1}{x}=2,$ then the value of $x^{12}-\frac{1}{x^{12}}$ is:
- A$4$
- B$2$
- C$0$
- D$-4$
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Similar Questions
Solve the given two equations and select the correct answer from the given options.
$I. 3x^2 - 4x - 32 = 0$
$II. 2y^2 - 17y + 36 = 0$
$I. 3x^2 - 4x - 32 = 0$
$II. 2y^2 - 17y + 36 = 0$
Difficult
View SolutionThe set of values of $x$ which satisfy $5x + 2 < 3x + 8$ and $\frac{x + 2}{x - 1} < 4$ is:
Easy
View SolutionIf $p$ and $q$ are the roots of $x^2 + px + q = 0$,then
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View SolutionIf a root of the given equation $a(b - c)x^2 + b(c - a)x + c(a - b) = 0$ is $1$,then the other root will be
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View SolutionThe values of $a$ and $b$ for which the equation $x^4 - 4x^3 + ax^2 + bx + 1 = 0$ has four real roots are:
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