If cot 3A = x, then the value of x is | vedclass

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(D) We know the trigonometric identity for $\cot 3A$ is given by:$\cot 3A = \frac{\cot^3 A - 3 \cot A}{3 \cot^2 A - 1}$Alternatively,by multiplying th

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$\frac{3 \cot A - \cot^3 A}{1 - 3 \cot^2 A}$

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(D) We know the trigonometric identity for $\cot 3A$ is given by:$\cot 3A = \frac{\cot^3 A - 3 \cot A}{3 \cot^2 A - 1}$Alternatively,by multiplying the numerator and denominator by $-1$,we get:$\cot 3A = \frac{3 \cot A - \cot^3 A}{1 - 3 \cot^2 A}$Since it is given that $\cot 3A = x$,the value of $x$ is $\frac{3 \cot A - \cot^3 A}{1 - 3 \cot^2 A}$.

If $\cot 3A = x,$ then the value of $x$ is

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