If tan x = (sin 45^{circ})(cos 45^{circ}) + s | vedclass

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(B) Given the equation: $	an x = \sin 45^{\circ} \cdot \cos 45^{\circ} + \sin 30^{\circ}$Substituting the standard trigonometric values:$\sin 45^{\ci

Vedclass · Accepted Answer

$45$

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(B) Given the equation: $	an x = \sin 45^{\circ} \cdot \cos 45^{\circ} + \sin 30^{\circ}$Substituting the standard trigonometric values:$\sin 45^{\circ} = \frac{1}{\sqrt{2}}$,$\cos 45^{\circ} = \frac{1}{\sqrt{2}}$,and $\sin 30^{\circ} = \frac{1}{2}$$	an x = \left(\frac{1}{\sqrt{2}}ight) \cdot \left(\frac{1}{\sqrt{2}}ight) + \frac{1}{2}$$	an x = \frac{1}{2} + \frac{1}{2}$$	an x = 1$Since $	an 45^{\circ} = 1$,we have $	an x = 	an 45^{\circ}$Therefore,$x = 45^{\circ}$.

If $\tan x = (\sin 45^{\circ})(\cos 45^{\circ}) + \sin 30^{\circ}$,then the value of $x$ is (in $^{\circ}$)

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