If 0

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(B) Given that $0 < a < 1$ and $0 < x < 1$.Since the base $a$ is between $0$ and $1$,the logarithmic function $f(x) = \log_{a} x$ is a strictly decrea

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$> 1$

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(B) Given that $0 Since the base $a$ is between $0$ and $1$,the logarithmic function $f(x) = \log_{a} x$ is a strictly decreasing function.Given the inequality $x Therefore,$\log_{a} x > \log_{a} a$.Since $\log_{a} a = 1$,we get $\log_{a} x > 1$.

If $0 < a < 1$,$0 < x < 1$,and $x < a$,then $\log_{a} x$ is:

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