If GO = 32, SHE = 49, then SOME will be equal | vedclass

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Question

(A) The logic used is that the position of each letter is taken from the end of the alphabet $(Z=1, Y=2, X=3, \dots, A=26)$.For $GO$: $G$ is $20^{th}$

Vedclass · Accepted Answer

$56$

Vedclass · Answer

(A) The logic used is that the position of each letter is taken from the end of the alphabet $(Z=1, Y=2, X=3, \dots, A=26)$.For $GO$: $G$ is $20^{th}$ from the end and $O$ is $12^{th}$ from the end. So, $20 + 12 = 32$.For $SHE$: $S$ is $8^{th}$, $H$ is $19^{th}$, and $E$ is $22^{nd}$ from the end. So, $8 + 19 + 22 = 49$.For $SOME$: $S$ is $8^{th}$, $O$ is $12^{th}$, $M$ is $14^{th}$, and $E$ is $22^{nd}$ from the end.Therefore, $SOME = 8 + 12 + 14 + 22 = 56$.

If $GO = 32$, $SHE = 49$, then $SOME$ will be equal to

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