If triangle ABC sim triangle DEF,AB = 4 , cm, | vedclass

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(C) Given that $	riangle ABC \sim 	riangle DEF$.Since the triangles are similar,the ratio of their corresponding sides is equal:$\frac{AB}{DE} = \fr

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(C) Given that $	riangle ABC \sim 	riangle DEF$.Since the triangles are similar,the ratio of their corresponding sides is equal:$\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}$.Substituting the given values:$\frac{4}{6} = \frac{BC}{9} = \frac{AC}{12}$.Now,solving for $BC$:$\frac{4}{6} = \frac{BC}{9} \implies BC = \frac{4 	imes 9}{6} = 6 \, cm$.Solving for $AC$:$\frac{4}{6} = \frac{AC}{12} \implies AC = \frac{4 	imes 12}{6} = 8 \, cm$.The perimeter of $	riangle ABC = AB + BC + AC$.Perimeter $= 4 + 6 + 8 = 18 \, cm$.

If $\triangle ABC \sim \triangle DEF$,$AB = 4 \, cm$,$DE = 6 \, cm$,$EF = 9 \, cm$,and $FD = 12 \, cm$,find the perimeter of $\triangle ABC$ (in $cm$).

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