If 2 sin^{2} theta - cos^{2} theta = 2,then f | vedclass

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(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equa

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(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equation:$2 \sin^{2} 	heta - (1 - \sin^{2} 	heta) = 2$Simplify the expression:$2 \sin^{2} 	heta - 1 + \sin^{2} 	heta = 2$$3 \sin^{2} 	heta - 1 = 2$Add $1$ to both sides:$3 \sin^{2} 	heta = 3$Divide by $3$:$\sin^{2} 	heta = 1$Taking the square root:$\sin 	heta = 1$ (considering the principal value)Since $\sin 90^{\circ} = 1$,we have:$	heta = 90^{\circ}$

Part $I$	Part $II$
$1.$ $\cos(90^\circ - \theta)$	$a.$ $\sec \theta$
$2.$ $\cot(90^\circ - \theta)$	$b.$ $\sin \theta$
$3.$ $\operatorname{cosec}(90^\circ - \theta)$	$c.$ $1$
	$d.$ $\tan \theta$

If $2 \sin^{2} \theta - \cos^{2} \theta = 2$,then find the value of $\theta$. (in $^{\circ}$)

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Which of the following groups truly matches the data of Part $I$ with the data of Part $II$?

Part $I$ Part $II$

$1.$ $\cos(90^\circ - \theta)$ $a.$ $\sec \theta$

$2.$ $\cot(90^\circ - \theta)$ $b.$ $\sin \theta$

$3.$ $\operatorname{cosec}(90^\circ - \theta)$ $c.$ $1$

$d.$ $\tan \theta$

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