If a=2 and d=4, then S_{40}=ldots ldots ldots | vedclass

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(C) The sum of the first $n$ terms of an Arithmetic Progression $(AP)$ is given by the formula: $S_n = \frac{n}{2} [2a + (n-1)d]$.Given values are $a

Vedclass · Accepted Answer

$3200$

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(C) The sum of the first $n$ terms of an Arithmetic Progression $(AP)$ is given by the formula: $S_n = \frac{n}{2} [2a + (n-1)d]$.Given values are $a = 2$,$d = 4$,and $n = 40$.Substituting these values into the formula:$S_{40} = \frac{40}{2} [2(2) + (40-1)4]$$S_{40} = 20 [4 + (39 	imes 4)]$$S_{40} = 20 [4 + 156]$$S_{40} = 20 [160]$$S_{40} = 3200$.Therefore,the correct option is $C$.

If $a=2$ and $d=4,$ then $S_{40}=\ldots \ldots \ldots$

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