(C) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(4

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(C) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(4, 7)$ and $B(7, 3)$.Substituting the values into the formula:$AB = \sqrt{(7 - 4)^2 + (3 - 7)^2}$$AB = \sqrt{(3)^2 + (-4)^2}$$AB = \sqrt{9 + 16}$$AB = \sqrt{25}$$AB = 5$.

Class 10 Mathematics Coordinate Geometry Mix Examples - Coordinate Geometry

Easy

If $A (4, 7)$ and $B (7, 3),$ then $AB = .............$

A
$3$
B
$4$
C
$5$
D
$7$

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Mix Examples - Coordinate Geometry

The point on the $Y-$ axis which is equidistant from $P(3,2)$ and $Q(-1,-5)$ is $\ldots \ldots \ldots \ldots$

Medium

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If $P(\frac{a}{3}, 4)$ is the mid-point of the line segment joining the points $Q(-6, 5)$ and $R(-2, 3)$,then the value of $a$ is

Medium

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Prove that the points $A(1, -2)$,$B(2, 3)$,$C(-3, 2)$,and $D(-4, -3)$ are the vertices of a rhombus.

Easy

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Using the distance formula,show that the points $A(7,3)$,$B(3,0)$,$C(0,-4)$,and $D(4,-1)$ are the vertices of a rhombus.

Medium

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Find the area of a pentagon having the vertices $(1, 5), (-2, 4), (-3, -1), (2, -3),$ and $(5, 1).$

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If $A (4, 7)$ and $B (7, 3),$ then $AB = .............$

Similar Questions

The point on the $Y-$ axis which is equidistant from $P(3,2)$ and $Q(-1,-5)$ is $\ldots \ldots \ldots \ldots$

If $P(\frac{a}{3}, 4)$ is the mid-point of the line segment joining the points $Q(-6, 5)$ and $R(-2, 3)$,then the value of $a$ is

Prove that the points $A(1, -2)$,$B(2, 3)$,$C(-3, 2)$,and $D(-4, -3)$ are the vertices of a rhombus.

Using the distance formula,show that the points $A(7,3)$,$B(3,0)$,$C(0,-4)$,and $D(4,-1)$ are the vertices of a rhombus.

Find the area of a pentagon having the vertices $(1, 5), (-2, 4), (-3, -1), (2, -3),$ and $(5, 1).$

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