If tan ^{2} theta = sin ^{2} theta + cos ^{2} | vedclass

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(C) Given the equation: $	an ^{2} 	heta = \sin ^{2} 	heta + \cos ^{2} 	heta$. We know the fundamental trigonometric identity: $\sin ^{2} 	heta +

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(C) Given the equation: $	an ^{2} 	heta = \sin ^{2} 	heta + \cos ^{2} 	heta$. We know the fundamental trigonometric identity: $\sin ^{2} 	heta + \cos ^{2} 	heta = 1$. Substituting this into the equation,we get: $	an ^{2} 	heta = 1$. Taking the square root on both sides: $	an 	heta = 1$ (considering the acute angle). Since $	an 45^{\circ} = 1$,we have $	heta = 45^{\circ}$.

If $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$,then $\theta = \ldots$ (in $^{\circ}$)

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