If P(A) : P(overline{A}) = 4 : 1,then P(overl | vedclass

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(C) We know that for any event $A$,the sum of the probability of the event and its complement is $1$,i.e.,$P(A) + P(\overline{A}) = 1$.Given the ratio

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$\frac{1}{5}$

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(C) We know that for any event $A$,the sum of the probability of the event and its complement is $1$,i.e.,$P(A) + P(\overline{A}) = 1$.Given the ratio $P(A) : P(\overline{A}) = 4 : 1$,we can let $P(A) = 4x$ and $P(\overline{A}) = 1x$ for some constant $x$.Substituting these into the sum equation: $4x + 1x = 1$.$5x = 1$,which gives $x = \frac{1}{5}$.Therefore,$P(\overline{A}) = 1x = 1 	imes \frac{1}{5} = \frac{1}{5}$.

If $P(A) : P(\overline{A}) = 4 : 1$,then $P(\overline{A}) = \ldots$

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