If (2x + 3)(3x - 1) = 6x^2 + kx - 3,then find | vedclass

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(A) To find the value of $k$,we expand the left side of the equation:$(2x + 3)(3x - 1) = 2x(3x) + 2x(-1) + 3(3x) + 3(-1)$$= 6x^2 - 2x + 9x - 3$$= 6x^2

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(A) To find the value of $k$,we expand the left side of the equation:$(2x + 3)(3x - 1) = 2x(3x) + 2x(-1) + 3(3x) + 3(-1)$$= 6x^2 - 2x + 9x - 3$$= 6x^2 + 7x - 3$Comparing this with the given equation $6x^2 + kx - 3$,we can see that the coefficient of $x$ is $k$ on the right side and $7$ on the expanded left side.Therefore,$k = 7$.

If $(2x + 3)(3x - 1) = 6x^2 + kx - 3$,then find the value of $k$.

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