If 1 mole of salt is dissolved in 2 liters of | vedclass

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(A) The concentration of a solution in Molarity $(M)$ is defined as the number of moles of solute dissolved per liter of solution.Formula: $M = \frac{

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$0.5$

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(A) The concentration of a solution in Molarity $(M)$ is defined as the number of moles of solute dissolved per liter of solution.Formula: $M = \frac{	ext{Number of moles of solute}}{	ext{Volume of solution in liters}}$Given:Number of moles of solute = $1\;	ext{mole}$Volume of solution = $2\;	ext{liters}$Calculation:$M = \frac{1\;	ext{mole}}{2\;	ext{liters}} = 0.5\;M$Therefore,the concentration of the solution is $0.5\;M$.

Column $(A)$	Column $(B)$
$(a)$ Plaster of Paris	$(i)$ $Ca(OH)_{2}$
$(b)$ Gypsum	$(ii)$ $CaSO_{4} \cdot 1/2 H_{2}O$
$(c)$ Bleaching Powder	$(iii)$ $CaSO_{4} \cdot 2H_{2}O$
$(d)$ Slaked Lime	$(iv)$ $CaOCl_{2}$

If $1$ mole of salt is dissolved in $2$ liters of salt solution,what is the concentration of the solution (in $;M$)?

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