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(D) The figure of merit $K$ of a galvanometer is defined as the current required to produce a unit deflection,given by $K = \frac{I_g}{n}$,where $I_g$

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$\frac{nK(G + S)}{S}$

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(D) The figure of merit $K$ of a galvanometer is defined as the current required to produce a unit deflection,given by $K = \frac{I_g}{n}$,where $I_g$ is the current through the galvanometer and $n$ is the number of deflections.Therefore,the current through the galvanometer is $I_g = Kn$.In a converted galvanometer (ammeter),the shunt resistance $S$ is connected in parallel with the galvanometer resistance $G$.Using the principle of current division in a parallel circuit,the total current $I$ is given by $I = I_g \left( \frac{G + S}{S} \right)$.Substituting $I_g = Kn$ into the equation,we get $I = \frac{nK(G + S)}{S}$.

$S. No.$	Resistance $R \ (\Omega)$	Deflection $(\theta)$	Shunt $S \ (\Omega)$	Half deflection $(\theta / 2)$	Galvanometer resistance $(G)$
$1$	$3300$	$30$	$80$	$15$	$G_1$
$2$	$5000$	$20$	$80$	$10$	$G_2$

If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$,then the total current $I$ when its figure of merit is $K$ will be:

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