If 1 , g of hydrogen is converted into 0.993 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The mass defect $\Delta m$ is the difference between the initial mass and the final mass.$\Delta m = 1 \, g - 0.993 \, g = 0.007 \, g$.Converting

Vedclass · Accepted Answer

$63 	imes 10^{10}$

Vedclass · Answer

(B) The mass defect $\Delta m$ is the difference between the initial mass and the final mass.$\Delta m = 1 \, g - 0.993 \, g = 0.007 \, g$.Converting the mass defect into $SI$ units (kilograms):$\Delta m = 0.007 	imes 10^{-3} \, kg = 7 	imes 10^{-6} \, kg$.The energy released $E$ is given by Einstein's mass-energy equivalence formula $E = \Delta m c^2$,where $c = 3 	imes 10^8 \, m/s$.$E = (7 	imes 10^{-6} \, kg) 	imes (3 	imes 10^8 \, m/s)^2$.$E = 7 	imes 10^{-6} 	imes 9 	imes 10^{16} \, J$.$E = 63 	imes 10^{10} \, J$.

If $1 \, g$ of hydrogen is converted into $0.993 \, g$ of helium in a thermonuclear reaction,the energy released in the reaction is ......... $J$.

Similar Questions

What was the fissionable material used in the bomb dropped at Nagasaki (Japan) in the year $1945$?

Which of the following isotopes is normally fissionable?

$A$ nucleus with mass number $220$ initially at rest emits an alpha particle. If the $Q$ value of the reaction is $5.5 \ MeV$,calculate the kinetic energy of the alpha particle. (in $MeV$)

The best neutron moderator is:

Suppose we think of the fission of a $^{56}_{26} Fe$ nucleus into two equal fragments,$^{28}_{13} Al$. Is the fission energetically possible? Argue by working out the $Q$-value of the process.
Given: $m(^{56}_{26} Fe) = 55.93494 \; u$ and $m(^{28}_{13} Al) = 27.98191 \; u$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module