If N_A is the number density of acceptor atom | vedclass

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(D) According to the law of electrical neutrality in a semiconductor,the total negative charge density must equal the total positive charge density.Th

Vedclass · Accepted Answer

$n_e + N_A = n_h + N_D$

Vedclass · Answer

(D) According to the law of electrical neutrality in a semiconductor,the total negative charge density must equal the total positive charge density.The negative charge carriers are electrons $(n_e)$ and ionized acceptor atoms $(N_A^-)$.The positive charge carriers are holes $(n_h)$ and ionized donor atoms $(N_D^+)$.Therefore,the charge neutrality equation is given by:$n_e + N_A = n_h + N_D$Thus,option $D$ is correct.

If $N_A$ is the number density of acceptor atoms added and $N_D$ is the number density of donor atoms added to a semiconductor,and $n_e$ and $n_h$ are the number density of electrons and holes in it,then:

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