If z is a complex number,then (overline {{z^{ | vedclass

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(A) We know that for any complex number $z$,the conjugate of the inverse is the inverse of the conjugate,i.e.,$\overline{z^{-1}} = (\overline{z})^{-1}

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(A) We know that for any complex number $z$,the conjugate of the inverse is the inverse of the conjugate,i.e.,$\overline{z^{-1}} = (\overline{z})^{-1}$.Therefore,$(\overline{z^{-1}})(\overline{z}) = (\overline{z})^{-1}(\overline{z})$.Since $(\overline{z})^{-1} = \frac{1}{\overline{z}}$,we have $\frac{1}{\overline{z}} 	imes \overline{z} = 1$,provided $z 
eq 0$.

If $z$ is a complex number,then $(\overline {{z^{ - 1}}} )(\overline z ) = $

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