If x + iy = sqrt{frac{a + ib}{c + id}},then ( | vedclass

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(A) Given $x + iy = \sqrt{\frac{a + ib}{c + id}}$.Taking the conjugate on both sides,we get $x - iy = \sqrt{\frac{a - ib}{c - id}}$.Now,multiplying th

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$\frac{a^2 + b^2}{c^2 + d^2}$

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(A) Given $x + iy = \sqrt{\frac{a + ib}{c + id}}$.Taking the conjugate on both sides,we get $x - iy = \sqrt{\frac{a - ib}{c - id}}$.Now,multiplying these two equations:$(x + iy)(x - iy) = \sqrt{\frac{a + ib}{c + id}} 	imes \sqrt{\frac{a - ib}{c - id}}$$x^2 + y^2 = \sqrt{\frac{(a + ib)(a - ib)}{(c + id)(c - id)}}$$x^2 + y^2 = \sqrt{\frac{a^2 + b^2}{c^2 + d^2}}$Squaring both sides,we get $(x^2 + y^2)^2 = \frac{a^2 + b^2}{c^2 + d^2}$.

If $x + iy = \sqrt{\frac{a + ib}{c + id}}$,then $(x^2 + y^2)^2 = $

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