If $\sum_{r=1}^9 \left(\frac{r+3}{2^r}\right) \cdot {}^9C_r = \alpha \left(\frac{3}{2}\right)^9 - \beta$,where $\alpha, \beta \in N$,then $(\alpha + \beta)^2$ is equal to

  • A
    $27$
  • B
    $9$
  • C
    $81$
  • D
    $18$

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