If $\varepsilon_0$ denotes the permittivity of free space and $\phi_{E}$ is the flux of the electric field through the area bounded by the closed surface,then the dimensions of $\left(\varepsilon_0 \frac{d \phi_{E}}{dt}\right)$ are that of

  • A
    Electric field
  • B
    Electric potential
  • C
    Electric charge
  • D
    Electric current

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