(D) The $pH$ of a solution is defined as $pH = -\log[H_3O^+]$.For $pH = 4$,$[H_3O^+]_1 = 10^{-4} \ M$.For $pH = 5$,$[H_3O^+]_2 = 10^{-5} \ M$.The chan

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(D) The $pH$ of a solution is defined as $pH = -\log[H_3O^+]$.For $pH = 4$,$[H_3O^+]_1 = 10^{-4} \ M$.For $pH = 5$,$[H_3O^+]_2 = 10^{-5} \ M$.The change in concentration is $\frac{[H_3O^+]_1}{[H_3O^+]_2} = \frac{10^{-4}}{10^{-5}} = 10$.Thus,the concentration decreases by $10$ times.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Water hydrolysis and pH scale

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If $pH$ of a solution changes from $4$ to $5$,then the $[H_3O^+]$ ion concentration of the solution:

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A
decreases by $1$ time
B
increases by $1$ time
C
increases by $10$ times
D
decreases by $10$ times

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6-2.Equilibrium-II (Ionic Equilibrium)

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If $pH$ of a solution changes from $4$ to $5$,then the $[H_3O^+]$ ion concentration of the solution:

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The standard Gibbs energy change in the reaction $H_2O \rightleftharpoons H^{+} + OH^{-}$ at $25\ ^oC$ is.....$kJ/mol$.

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