यदि $y = \frac{\sin x}{1 + \frac{\cos x}{1 + \frac{\sin x}{1 + \dots}}}$,तो $\frac{dy}{dx}$ का मान ज्ञात कीजिए।

  • A
    $\frac{y \sin x + (1 + y) \cos x}{1 + 2y + \cos x - \sin x}$
  • B
    $\frac{y \cos x + (1 + y) \sin x}{1 + 2y + \cos x - \sin x}$
  • C
    $\frac{y \sin x - (1 + y) \cos x}{1 + 2y + \cos x - \sin x}$
  • D
    $\frac{y \cos x - (1 + y) \sin x}{1 + 2y + \cos x - \sin x}$

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Similar Questions

यदि $y = \sqrt{\log(x^2+1) + \sqrt{\log(x^2+1) + \sqrt{\log(x^2+1) + \dots \infty}}}$, $|x| < 1$, तो $\frac{dy}{dx} = $

यदि $y = e^{x + e^{x + e^{x + \dots \infty}}}$,तो $\frac{dy}{dx} = $

यदि $ y=\sqrt{x+\sqrt{x+\sqrt{x+\ldots \infty}}} $ है,तो $ \frac{d y}{d x}= $

यदि $y = e^{x^2 + e^{x^2 + e^{x^2} + \dots}}$ है,तो $\frac{dy}{dx} = $

यदि $y = \frac{x}{a + \frac{x}{b + \frac{x}{a + \frac{x}{b + \dots \infty}}}},$ है,तो $\frac{dy}{dx} = $

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