If $f(x)=\frac{3x+4}{5x-7}$ and $g(x)=\frac{7x+4}{5x-3}$,then $f(g(x))=$

  • A
    $\frac{x^3+1}{x^2+2}$
  • B
    $41x$
  • C
    $g(f(x))$
  • D
    $\frac{5x-7}{41}$

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