If ${(p \wedge \sim q) \wedge (p \wedge r)} \rightarrow (\sim p \vee q)$ has a truth value of $False$,then the truth values of the statements $p, q, r$ are respectively:

  • A
    $T, T, T$
  • B
    $F, F, F$
  • C
    $F, F, T$
  • D
    $T, F, T$

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Similar Questions

Consider the following statements:
$r: \text{If } p \to q \text{ is false, then } p \lor q \text{ is false.}$
$s: \text{If } p \leftrightarrow q \text{ is false, then } p \lor q \text{ is false.}$
The truth values of $r \to s$ and $s \to r$ are respectively:

Let,$p$: Ramesh listens to music.
$q$: Ramesh is out of his village.
$r$: It is Sunday.
$s$: It is Saturday.
Then the statement "Ramesh listens to music only if he is in his village and it is Sunday or Saturday" can be expressed as:

If $P$ and $Q$ are two statements,then which of the following compound statements is a tautology?

The negation of the statement pattern $\sim s \vee (\sim r \wedge s)$ is equivalent to

Write the negation of the following statement:
All triangles are not equilateral triangles.

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