If 3 books on Physics,2 books on Chemistry,an | vedclass

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Question

(C) There are $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics. Since all Physics books must be together,we treat them as $1$

Vedclass · Accepted Answer

$3456$

Vedclass · Answer

(C) There are $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics. Since all Physics books must be together,we treat them as $1$ unit. Since all Mathematics books must be together,we treat them as $1$ unit. There are $2$ individual Chemistry books. Thus,we have $1$ (Physics unit) + $1$ (Mathematics unit) + $2$ (Chemistry books) = $4$ units to arrange. These $4$ units can be arranged in $4!$ ways. The $3$ Physics books can be arranged among themselves in $3!$ ways. The $4$ Mathematics books can be arranged among themselves in $4!$ ways. $	herefore 	ext{Total arrangements} = 4! 	imes 3! 	imes 4! = 24 	imes 6 	imes 24 = 3456$.

If $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics are to be arranged on a shelf so that all the Physics books are together and all the Mathematics books are together,then the number of such arrangements is

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