If A and B are two independent events and P(A | vedclass

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(B) Given that $A$ and $B$ are independent events,$P(A) = \frac{3}{5}$ and $P(B) = \frac{2}{3}$.We need to find $P(A' \cap B')$.Since $A$ and $B$ are

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$\frac{2}{15}$

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(B) Given that $A$ and $B$ are independent events,$P(A) = \frac{3}{5}$ and $P(B) = \frac{2}{3}$.We need to find $P(A' \cap B')$.Since $A$ and $B$ are independent,$A'$ and $B'$ are also independent.Therefore,$P(A' \cap B') = P(A') \cdot P(B')$.First,calculate $P(A')$ and $P(B')$:$P(A') = 1 - P(A) = 1 - \frac{3}{5} = \frac{2}{5}$.$P(B') = 1 - P(B) = 1 - \frac{2}{3} = \frac{1}{3}$.Now,calculate the product:$P(A' \cap B') = \frac{2}{5} 	imes \frac{1}{3} = \frac{2}{15}$.Thus,the correct option is $B$.

If $A$ and $B$ are two independent events and $P(A)=\frac{3}{5}$ and $P(B)=\frac{2}{3}$,then $P(A' \cap B')=$

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