If $\theta$ and $\alpha$ are not odd multiples of $\frac{\pi}{2}$,then $\tan \theta = \tan \alpha$ implies the general solution is

• A
  $\theta = \alpha + \frac{n \pi}{2}, n \in Z$
• B
  $\theta = \alpha + \frac{3 n \pi}{2}, n \in Z$
• C
  $\theta = n \pi + \alpha, n \in Z$
• D
  $\theta = \frac{n \pi}{4} + \alpha, n \in Z$