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The expression $[1 - \sin(3\pi - \alpha) + \cos(3\pi + \alpha)] [1 - \sin(\frac{3\pi}{2} - \alpha) + \cos(\frac{5\pi}{2} - \alpha)]$ when simplified reduces to:

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Find the value of the trigonometric function $\csc(-1410^{\circ})$.

If $\sin x = -\frac{24}{25},$ then the value of $\tan x$ is

$\operatorname{cosec} 15^{\circ} + \sec 15^{\circ}$ is equal to :

The value of $(1+\cos \frac{\pi}{6})(1+\cos \frac{\pi}{3})(1+\cos \frac{2\pi}{3})(1+\cos \frac{7\pi}{6})$ is

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